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authorUnknwon <u@gogs.io>2017-02-09 19:48:13 -0500
committerUnknwon <u@gogs.io>2017-02-09 19:48:13 -0500
commit2fd69f13d9599a6c58b47225565163fd7d87889f (patch)
treefd19e868e1c2e95a5fb83a268f6e393669d6ee79 /vendor/github.com/issue9/identicon/polygon.go
parenteb66060cd7b9bce996b1d75ae80ce1ef31d5ce62 (diff)
vendor: check in vendors
Bye bye glide...
Diffstat (limited to 'vendor/github.com/issue9/identicon/polygon.go')
-rw-r--r--vendor/github.com/issue9/identicon/polygon.go69
1 files changed, 69 insertions, 0 deletions
diff --git a/vendor/github.com/issue9/identicon/polygon.go b/vendor/github.com/issue9/identicon/polygon.go
new file mode 100644
index 00000000..06759c31
--- /dev/null
+++ b/vendor/github.com/issue9/identicon/polygon.go
@@ -0,0 +1,69 @@
+// Copyright 2015 by caixw, All rights reserved.
+// Use of this source code is governed by a MIT
+// license that can be found in the LICENSE file.
+
+package identicon
+
+var (
+ // 4个元素分别表示cos(0),cos(90),cos(180),cos(270)
+ cos = []float64{1, 0, -1, 0}
+
+ // 4个元素分别表示sin(0),sin(90),sin(180),sin(270)
+ sin = []float64{0, 1, 0, -1}
+)
+
+// 将points中的所有点,以x,y为原点旋转angle个角度。
+// angle取值只能是[0,1,2,3],分别表示[0,90,180,270]
+func rotate(points []float64, x, y float64, angle int) {
+ if angle < 0 || angle > 3 {
+ panic("rotate:参数angle必须0,1,2,3三值之一")
+ }
+
+ for i := 0; i < len(points); i += 2 {
+ px := points[i] - x
+ py := points[i+1] - y
+ points[i] = px*cos[angle] - py*sin[angle] + x
+ points[i+1] = px*sin[angle] + py*cos[angle] + y
+ }
+}
+
+// 判断某个点是否在多边形之内,不包含构成多边形的线和点
+// x,y 需要判断的点坐标
+// points 组成多边形的所顶点,每两个元素表示一点顶点,其中最后一个顶点必须与第一个顶点相同。
+func pointInPolygon(x float64, y float64, points []float64) bool {
+ if len(points) < 8 { // 只有2个以上的点,才能组成闭合多边形
+ return false
+ }
+
+ // 大致算法如下:
+ // 把整个平面以给定的测试点为原点分两部分:
+ // - y>0,包含(x>0 && y==0)
+ // - y<0,包含(x<0 && y==0)
+ // 依次扫描每一个点,当该点与前一个点处于不同部分时(即一个在y>0区,一个在y<0区),
+ // 则判断从前一点到当前点是顺时针还是逆时针(以给定的测试点为原点),如果是顺时针r++,否则r--。
+ // 结果为:2==abs(r)。
+
+ r := 0
+ x1, y1 := points[0], points[1]
+ prev := (y1 > y) || ((x1 > x) && (y1 == y))
+ for i := 2; i < len(points); i += 2 {
+ x2, y2 := points[i], points[i+1]
+ curr := (y2 > y) || ((x2 > x) && (y2 == y))
+
+ if curr == prev {
+ x1, y1 = x2, y2
+ continue
+ }
+
+ mul := (x1-x)*(y2-y) - (x2-x)*(y1-y)
+ if mul > 0 {
+ r++
+ } else if mul < 0 {
+ r--
+ }
+ x1, y1 = x2, y2
+ prev = curr
+ }
+
+ return r == 2 || r == -2
+}